Merge Sorted Array
Problem
You are given two integer arrays nums1
and nums2
, sorted in non-decreasing order, and two integers m
and n
, representing the number of elements in nums1
and nums2
respectively.
Merge nums1
and nums2
into a single array sorted in non-decreasing order.
The final sorted array should not be returned by the function, but instead be stored inside the array nums1
. To accommodate this, nums1
has a length of m + n
, where the first m
elements denote the elements that should be merged, and the last n
elements are set to 0
and should be ignored. nums2
has a length of n
.
Solution Approach
Click - to see solution code
- C++
class Solution {
public:
void merge(vector<int>& arr1, int m, vector<int>& arr2, int n) {
vector<int> arr(m + n);
int i = 0, j = 0, k = 0;
while (i < m && j < n) {
if (arr1[i] <= arr2[j])
arr[k++] = arr1[i++];
else
arr[k++] = arr2[j++];
}
while (i < m) arr[k++] = arr1[i++];
while (j < n) arr[k++] = arr2[j++];
arr1 = arr;
}
};